If it's not what You are looking for type in the equation solver your own equation and let us solve it.
n^2=121/49
We move all terms to the left:
n^2-(121/49)=0
We add all the numbers together, and all the variables
n^2-(+121/49)=0
We get rid of parentheses
n^2-121/49=0
We multiply all the terms by the denominator
n^2*49-121=0
Wy multiply elements
49n^2-121=0
a = 49; b = 0; c = -121;
Δ = b2-4ac
Δ = 02-4·49·(-121)
Δ = 23716
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{23716}=154$$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-154}{2*49}=\frac{-154}{98} =-1+4/7 $$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+154}{2*49}=\frac{154}{98} =1+4/7 $
| x7+9=58 | | 3x-9=-1-4x | | 2x+12=-4+10x | | -4(x+1)=6x-54 | | -45=-3(2b+5 | | x²+18=82 | | 6x=45=3(x+8) | | b+3/b-2=4/5 | | 5-3(2x-7)=2(7-3x+) | | 6(x-3)-2x=10 | | 7x=15=85 | | -3=4x+4 | | -n-12=-3n+8 | | -3(4x+3)+4(6x+1)=2(x-1) | | m+12=-30 | | 3(z-1)=12 | | 1.95x+6.375=7.055+1.85x | | (z-1)(z+2)=(z=4)(z-2) | | 3x-4-5x=6+4x+2 | | 15=q/3-2 | | n^2=223/49 | | 4(5+2x)-2=3(3x+7) | | 3x+80=3x+20 | | -8x+48=-80 | | 10-4t=-10+t | | 5x-36=2(-7x+1) | | 7x-2=45 | | 5x+2=11x+12 | | 26=-19+y | | 1/4x-6=-14 | | -4(1+6x)=-30+2x | | 60=4(x+4) |